User:Karsten Theis/turns

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</jmol>
</jmol>
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===Excercise 1===
Try to use the buttons to make a type 1 turn with the features shown below. Are there any clashes? How is the different from an alpha helix (where all carbonyl groups are pointing in the same direction)?
Try to use the buttons to make a type 1 turn with the features shown below. Are there any clashes? How is the different from an alpha helix (where all carbonyl groups are pointing in the same direction)?
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[[Image:Beta_turn_type_I.png|500px]]
[[Image:Beta_turn_type_I.png|500px]]
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<jmol>
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<jmolButton>
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<script>rphi2 = -60 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = -30 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -90 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 0 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3; center visible</script>
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===Excercise 2===
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<text>Type I</text>
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</jmolButton>
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</jmol><jmol>
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<jmolButton>
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<script>rphi2 = -57 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = -47 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -57 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = -47 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3; center visible</script>
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<text>(alpha helix)</text>
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</jmolButton>
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</jmol><jmol>
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<jmolButton>
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<script>rphi2 = -140 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = 130 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -140 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 130 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3; center visible</script>
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<text>(beta strand)</text>
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</jmolButton>
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</jmol>
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And now try to get a type I prime conformation, as shown below. Hint: the pepflip button might serve as a bit of a shortcut. Why is that? Are there any clashes? If you had to choose, would you place a glycine at position 2 or position 3?
And now try to get a type I prime conformation, as shown below. Hint: the pepflip button might serve as a bit of a shortcut. Why is that? Are there any clashes? If you had to choose, would you place a glycine at position 2 or position 3?
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[[Image:Beta_turn_type_I_prime.png|500px]]
[[Image:Beta_turn_type_I_prime.png|500px]]
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<jmol>
 
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<jmolButton>
 
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<script>rphi2 = 60 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = 30 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = 90 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 0 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3</script>
 
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<text>Type I prime</text>
 
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</jmolButton>
 
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</jmol><jmol>
 
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<jmolButton>
 
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<script>rotate X 180</script>
 
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<text>flip along x-axis</text>
 
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</jmolButton>
 
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</jmol>
 
Phi&emsp;<jmol>
Phi&emsp;<jmol>
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</jmolButton>
</jmolButton>
</jmol>
</jmol>
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Psi&emsp;<jmol>
Psi&emsp;<jmol>
<jmolButton>
<jmolButton>
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</jmol>
</jmol>
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===Exercise 3===
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Compare and contrast the two turns we discussed, and compare them to alpha helix and beta sheet. Clicking the buttons will preserve the orientation of the 2->3 peptide plane while adjusting the torsion angles. You can press the last button to flip the entire molecules as a rigid body (different from the pepflip button above, which changes torsion angles).
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<jmol>
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<jmolButton>
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<script>rphi2 = -60 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = -30 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -90 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 0 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3; center visible</script>
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<text>Type I</text>
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</jmolButton>
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</jmol> <jmol>
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<jmolButton>
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<script>rphi2 = -57 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = -47 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -57 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = -47 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3</script>
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<text>(alpha helix)</text>
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</jmolButton>
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</jmol> <jmol>
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<jmolButton>
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<script>rphi2 = -140 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = 130 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = -140 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 130 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3</script>
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<text>(beta strand)</text>
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</jmolButton>
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</jmol> <jmol>
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<jmolButton>
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<script>rphi2 = 60 - angle({67.C},{68.N},{68.CA},{68.C});rotate branch {68.CA} {68.N} @rphi2;rpsi2 = 30 - angle({68.N},{68.CA},{68.C},{69.N});rotate branch {68.C} {68.CA}@rpsi2;rphi3 = 90 - angle({68.C},{69.N},{69.CA},{69.C});rotate branch {69.N} {69.CA} @rphi3;rpsi3 = 0 - angle({69.N},{69.CA},{69.C},{70.N});rotate branch {69.CA} {69.C} @rpsi3</script>
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<text>Type I prime</text>
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</jmolButton>
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</jmol> <jmol>
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<jmolButton>
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<script>rotate X 180</script>
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<text>flip along x-axis</text>
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</jmolButton>
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</jmol>
.
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Revision as of 21:13, 7 February 2025

A beta turn is a secondary structure element consisting of four consecutive amino acids (or three peptide planes). The geometry of turns correspond to a change in the direction of the polypeptide backbone, allowing them to connect alpha helices and beta strands at the surface of a globular protein. Of the six main chain hydrogen bonding partners of a turn, a maximum of two are engaged in hydrogen bonding, and turns are rarely found in the hydrophobic core.

Exploring turns

Drag the structure with the mouse to rotate

Proteopedia Page Contributors and Editors (what is this?)

Karsten Theis

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